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\newcommand{\coursenumber}{Math 042}
\newcommand{\coursetitle}{Intermediate Algebra}
\newcommand{\docdate}{February 24, 2010}
\newcommand{\duedate}{February 24, 2010}
\newcommand{\doctitle}{Exam I}
\newcommand{\student}{PUT YOUR NAME HERE}

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\begin{document}

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%\paragraph{}
%The point value of each problem is shown in [ ]. To receive full
%credit all your answers should be carefully justified.
%Each solution must be the student's own work. 

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\begin{center}\framebox{\parbox{\boxlength}{\bf
Math 042: Exam I \hfill Date: Feb 24, 2010\\ ~\\~\\
Name: $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$    \hfill Section: $\_\_\_\_\_\_\_\_\_\_\_\_\_$}}
\end{center}

%\problembreak
\noindent
\paragraph{1.} Simplify: $7a^3-2a^2 -(5a^2-6)$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.6in}

\paragraph{2.}
Solve for $x$: $5x-9=2x-16$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .


\newpage
\paragraph{3.}
Solve for $x$: $\frac{2}{3}x - 1 = \frac{3}{4}x$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{1.8in}


\paragraph{4.} 
Simplify: $\frac{(5a/7b^2)}{(15/8ab)}$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.0in}

\paragraph{5.}
Evaluate: $-a^2 + 3b^3$ for $a=6$, $b=-3$\\

\ni
(a) 45 \hspace*{0.1in} (b) -45 \hspace*{0.1in} (c) 117 \hspace*{0.1in}
(d) -117

\newpage
\paragraph{6.}
Simplify: $\frac{(3ab)^2}{9a^2b^3}$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{1.6in}

\paragraph{7.}
Solve the inequality: $-2(y+4) > 18$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{1.8in}

%\paragraph{8.}
%Solution to the compound inequality $x<-4$ or $x<0$ is\\
%
%\ni
%(a) $(-4,0)$ \hspace*{0.1in} (b) $(-\infty,0)$ \hspace*{0.1in} (c) $(-\infty,4)$ \hspace*{0.1in}
%(d) all reals

\paragraph{8.}
Solve for $c$: $f = \frac{9}{5}c + 32$\\

\ni
(a) $\frac{5(f-32)}{9}$\hspace*{0.1in}(a) $\frac{5f-32}{9}$   \hspace*{0.1in} (c) $\frac{9}{5}f-32$ \hspace*{0.1in}
(d) $\frac{5f}{9}-32$

%\vspace*{1.0in}

\newpage
\paragraph{9.}
Solve for $x$: $cx+b = ax -d$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\vspace*{1.6in}

\paragraph{10.}
160\% of what number is 80?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\vspace*{1.7in}

\paragraph{11.}
72 is what percent of 90?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\vspace*{1.8in}

\paragraph{12.}
6 times the sum of a number and its cube can be represented by\\

\ni
(a) $6(n+n^3)$\hspace*{0.1in} (b) $6(n+n)^3$ \hspace*{0.1in} (c) $6+n+n^3$ \hspace*{0.1in}
(d) $6n+n^2$


\newpage
\paragraph{13.}
The length of a rectangle is 5 less than twice its width. What can be
used to represent its perimeter?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.2in}

\paragraph{14.} 
An RCA employee earned \$240 a week. If \$32 is deducted for taxes,
\$25 for health benefits and \$15 for pension, what percent of  the
salary is left?\\

\ni
(a)  30\%\hspace*{0.1in} (b) 70\% \hspace*{0.1in} (c) 72\% \hspace*{0.1in}
(d) 168\%


\vspace*{2.2in}

\paragraph{15.}
If \$1100 is invested at $t$\% and \$700 is invested at $(t-2)\%$ what
can be used to represent the interest drawn in one year?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\end{document}