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\newcommand{\coursenumber}{Math 042}
\newcommand{\coursetitle}{Intermediate Algebra}
\newcommand{\docdate}{October 11, 2010}
\newcommand{\duedate}{October 11, 2010}
\newcommand{\doctitle}{Exam I}
\newcommand{\student}{PUT YOUR NAME HERE}

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\begin{document}

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%\begin{center}
%\Large\bf\coursenumber\\[2pt]\doctitle \\ \large\docdate
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%\paragraph{}
%The point value of each problem is shown in [ ]. To receive full
%credit all your answers should be carefully justified.
%Each solution must be the student's own work. 

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\begin{center}\framebox{\parbox{\boxlength}{\bf
Math 042: Exam I \hfill Date: Oct 11, 2010\\ ~\\~\\
Name: $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$    \hfill Section: $\_\_\_\_\_\_\_\_\_\_\_\_\_$}}
\end{center}

%\problembreak
\noindent
\paragraph{1.} Simplify: $8a^3-3a^2 -(4a^2-5)$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.6in}

\paragraph{2.}
Solve for $x$: $-3x+5=-5x-8$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .


\newpage
\paragraph{3.}
Solve for $x$: $\frac{4}{3}x - 6 = \frac{3}{2}x$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{1.8in}


\paragraph{4.} 
Simplify: $\frac{(6x^2y/11)}{(9y^2/22)}$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.0in}

\paragraph{5.}
Evaluate: $-a^2 + 3b^3$ for $a=5$, $b=-3$.\\
%
%\ni
%(a) 106 \hspace*{0.1in} (b) -106 \hspace*{0.1in} (c) 56 \hspace*{0.1in}
%(d) -56

\newpage
\paragraph{6.}
Simplify: $\frac{(3xy)^2}{9x^2y^3}$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.0in}

\paragraph{7.}
Solve the inequality: $-3(y-1) < 12$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.0in}

%\paragraph{8.}
%Solution to the compound inequality $x>-4$ or $x>0$ is\\
%
%\ni
%(a) $(-4,0)$ \hspace*{0.1in} (b) $(0,\infty)$ \hspace*{0.1in} (c) $(-4,\infty)$ \hspace*{0.1in}
%(d) all reals

%\paragraph{8.}
%Solve for $c$: $f = \frac{9}{5}c + 32$\\
%
%\ni
%(a) $\frac{5f-32}{9}$ \hspace*{0.1in} (b) $\frac{5(f-32)}{9}$ \hspace*{0.1in} (c) $\frac{5f}{9}-32$ \hspace*{0.1in}
%(d) $\frac{9}{5}f-32$
\paragraph{8.}
What is the  slope of the line given by the equation $x=-5$?\\
%
%\ni
%(a) 1 \hspace*{0.1in} (b) 0 \hspace*{0.1in} (c) $-5$ \hspace*{0.1in}
%(d) undefined

\newpage
\paragraph{9.}
Solve for $x$: $ax+d = cx -b$\\

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\vspace*{1.9in}

\paragraph{10.}
If 30 is 120\% of a number, what is the number?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .


\vspace*{1.7in}

\paragraph{11.}
What is 20\% of 75?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\vspace*{1.8in}

\paragraph{12.}
6 times the sum of a number and its cube can be represented by\\

\ni
(a)  $6n+n^2$\hspace*{0.1in} (b) $6(n+n)^3$ \hspace*{0.1in} (c) $6+n+n^3$ \hspace*{0.1in}
(d) $6(n+n^3)$



\newpage
\paragraph{13.}
The length of a rectangle is 5 less than twice its width. What can be
used to represent its perimeter?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .
\vspace*{2.0in}

\paragraph{14.} 
An RCA employee earned \$280 a week. If \$52 is deducted for taxes,
\$35 for health benefits and \$25 for pension, what percent of  the
salary is left?\\

\ni
(a)  168\%\hspace*{0.1in} (b) 112\% \hspace*{0.1in} (c) 60\% \hspace*{0.1in}
(d) 40\%


\vspace*{1.8in}

\paragraph{15.}
If \$1300 is invested at $t$\% and \$600 is invested at $(t-3)\%$ what
can be used to represent the interest drawn in one year?\\

\ni
\textbf{Your answer: } $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\newpage
\paragraph{16.}
Which of the following is the graph of $-3x+y=-6$?

\begin{figure}[ht]
\centering
\includegraphics[width=4.5in]{q16.eps}
\label{fig:1}
\end{figure}

~\\
\vspace*{0.8in}

\paragraph{17.}
Find the slope of the line
and is \textbf{perpendicular} to the line passing through $(-2,5)$ and $(3,-3)$. \\

\ni
\textbf{Slope:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .\\

\vspace*{1.6in}


\newpage
\paragraph{18.} 
Find the equation of the line passing through $(2,-3)$ with slope of $3/2$.\\ 

\ni
\textbf{Equation:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .

\vspace*{1.6in}

\paragraph{19.}
Solve the following system of equations.
\begin{eqnarray*}
2x - y & = & 1 \\
-3x + 2y & = & 5 
\end{eqnarray*}

\ni
\textbf{Your answer:} $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ .


\vspace*{1.6in}

\paragraph{20.}
Graph $3x+2y < 6$.

\begin{figure}[h]
\centering
\includegraphics[width=2.0in]{q20.eps}
\label{fig:6}
\end{figure}

\end{document}