Homework assignments


Instructions:

You will be assigned two problems per class to be handed in for credit. The following instructions must be obeyed exactly.

1. On the class sign-in sheet, alongside your name there is a number, 1, 2, 3, ... etc. You will use this number for the whole semester (If you were in the class last semester, your number has probably changed.).

2. Each assigned problem will be taken from the textbook, but one of the input numbers is replaced by a formula, so that you can calculate the value from your personal number. In this way, each student has a different value to work with.

3. Solve the problem, using your own input value, and calculate the answer to five significant figures, however many figures the numbers are given to in the problem.

4. The problems for each class will appear as an "Assignment" in Sakai. I suggest you work out the problem before logging on to Sakai. You will submit your answers on-line.

5. Your answer must be submitted before the next lecture. No late answers will be accepted.

6. Unless otherwise instructed, use the same units given in the problem e.g. if distances are given in meters use meters and use the values for the physical constants given inside the back cover of the text book.

Example: Problem 21-2. A particle of charge +3.00 x 10-6 C is 12.0 cm distance from a second particle of charge -1.50 x 10-6 C. Calculate the magnitude of the electrostatic force between the particles.

Your instructions are to replace 3.00 x 10-6 C with (2.00 + n/50) x 10-6 C. If you are number 37 on the class list, (2.00 + n/50) is (2.00 + 37/50) = 2.74. So you would work the problem using 2.74 x 10-6 C instead of 3.00 x 10-6 C.


Assigned Problems


Date Problem Value Replace with formula
1/17/07 21-2 3.00 x 10-6 C (2.00+n/50) x 10-6 C
21-23 1.0 x 10-7 C (1.0 + n/10) x 10-7 C
1/22/07 22-6 21.0 cm (12.0+n/10) cm
give magnitude of the field
22-12 (a) 6.00 mm (8.00 + n/100) mm
1/24/07 22-11 5.00 cm (5.00+n/10) cm
give magnitude of the field
22-43 (b) 2.0 cm (1.50 + n/100) cm
1/29/07 23-1 3.2 mm (2.00+n/100) mm
23-9 60.0 N/C (10.0 + n) N/C
1/31/07 23-43 15 cm (12.0+n/10) cm
23-25 (a) 4.0 cm (3.50+n/20) cm
2/05/07 24-5 (b) 3.9 x 10-15 N (2.00+n/20) x 10-15 N
24-15 4.00 cm (3.50+n/20) cm
2/07/07 24-31 (3.0 m, 2.0 m) {3(1+n/100), 2(1+n/100)}m
24-57 (b) 15 cm (10.0+n/10) cm
2/12/07 25-9 10.0 mF (5.0 + n/10) mF
25-26 (c) 40 cm2 (20 + n) cm2
2/21/07 26-15 50 mW (20.0+n/2) mW
26-45 (b) 4.0 m (2.00+n/20) m
2/26/07 27-4 (all parts) 2.0 V (1.50+n/100) V
27-8 (a) 1.0 mA (1.50 + n/100) mA
2/28/07 27-15 18.0 W (10.0 + n/10) W
27-33 (a) e1 = 3.00 V (3.0 + n/10) V
3/05/07 27-47 (b) 5.00 V (6.00+n/50) V
28-35 62 cm (40.0+n/2) cm
3/07/07 28-7 1.0 kV (1.00+n/50) kV
give magnitude of the field
28-19 (b) 35 mT (10.0 + n/2) mT
3/19/07 29-1 (a) 6.1 m (5.00+n/100) m
29-33 a = 10 cm (2.0 + n/10) cm
give magnitude of force
3/21/07 29-37 (b) Find field at r = (1.00+n/100) cm
30-4 10 cm (5.0 + n/10) cm
3/26/07 30-27 50 cm (50+n) cm
30-51 10 mA (5.0+n/10) mA
4/02/07 31-9 50 mH (20.0+n/2) mH
31-21 (c) 64.0 mF (20.0+n/2) mF
4/04/07 31-46 (c) 150 mH (160+n) mH
31-52 100 V (20 + 2n) V
4/09/07 33-12 (b) 5.00 V/m (6.00+n/10) V/m
33-33 40o, 20o, 40o (16 + n/2),(8+n/4),(16+n/2)o
4/11/07 33-55 80.0 cm (30+n) cm
34-7 2.50 (1.5+n/10)
4/16/07 34-47 27 m (15.0 + n/5) m
34-58 (b) 40 cm (20+n) cm
4/18/07 34-87 (a) 20 cm (16.0+n/10) cm
34-93 (b) 100 cm (50 + n) cm
4/23/07 35-85 (a) 4.0 m/s (4.20 + n/50) m/s
35-19 1.20 mm (0.80+n/100) mm
4/25/07 36-7 589 nm (400 + 4n) nm
36-43 20 o (21.0 + n/5) o